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Sep 17, 2007 · A ball is tossed from an upper story window of a building. The ball is given an initial velocity of 8.0m/s at an angle of 20.0 below the horizontal. It strikes the ground 3.00s later. a) How far horizontally from the base of the building does the ball strike the ground? b) Find the height from which the ball was thrown The initial height from which the ball is thrown is, h =20m h = 20 m. The initial speed of the ball is, u =5 m/s u = 5 m / s. The ball is thrown horizontally. So angle with X axis is, θ =0∘ θ = 0 ∘

A ball is thrown upward from the ground with an initial speed of 25ms^-1. At the same instant , another ball is dropped from a 15m building . When wil two balls be at the same height from the ground?
A ball is dropped from a building of height 45 m. Simultaneously another ball is thrown up with a speed of 40 m/s. Calculate the relative speed of the balls as a function of time. Scribd is the world's largest social reading and publishing site.

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For the first bit you can use $s=\frac{1}{2}gt^2$ so $55=\frac{1}{2}*9.8*t^2$ $t^2=11.22\,\,\,\, so\,\,\,\,\, t=3.35s$ The key to ...
May 27, 2019 · A ball is thrown horizontally at 8m/s from the tower. It reaches the ground after 4 seconds.Calculate the height of the tower. A ball is thrown horizontally at 8m/s from the tower. It reaches the ground after 4 seconds.Calculate the hei Get the detailed answer: A ball thrown horizontally at 29 m/s travels a horizontal distance of54 m before hitting the ground.From what height was the ball

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A horizontally-thrown ball begins to fall as soon as it leaves your hand. It hits the ground some distance from you, but at the same instant as if you had just dropped it from your hand.
a ball thrown horizontally with velocity v from the top of a tower of height h reaches the ground in t second.If another ball of double the mass is thrown - 3769729 A ball thrown horizontally at 24.2 m/s from the roof of a building lands 33.0 m from the base of the building.How high is the building? Q. Extreme-sports enthusiasts have been known to jump off the top of El Capitan, a sheer granite cliff of height 910 m in Yosemite National Park.

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Objects thrown horizontally will spend the same amount of time in the air as objects that are in free-fall from the same height, d y. So, we can calculate the time in the air using d y = v y t air + ½gt 2 air , where v y = 0 m/s and thus d y = ½gt 2 air .
Here are the usual approximations that we make for a problem like this. (Without them, then the question cannot be answered without providing MANY more details.) 1. The ground is flat. 2. We can ignore any forces acting on the ball other than gra...

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For the first bit you can use $s=\frac{1}{2}gt^2$ so $55=\frac{1}{2}*9.8*t^2$ $t^2=11.22\,\,\,\, so\,\,\,\,\, t=3.35s$ The key to ...
May 01, 2019 · A ball is thrown horizontally from a height with a certain initial velocity at time t = 0. The ball bounces repeatedly from the ground with the coefficient of restitution less than 1 as shown Neglect air resistance and taking the upward direction as positive, which figure qualitatively depicts the vertical component of the ballís velocity (V y ... Answer: 78.4m. Explanation: In these situations, vertical and horizontal components need to be considered separately; So, horizontal speed is irrelevant since we are talking about vertical height, i.e. the height of the cliff; But, the fact that the speed is horizontal is relevant because this means the vertical speed initially is 0m/s; The downwards movement of the ball is due to gravity, which is 9.8m/s²;

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